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Home / Doubts and Solutions/JEE/Physics

Sir here in answer of loop-3 it is given that integralB.dl=-(mu not)i, so please can u explain it

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Asked by jaychandran1967 19th September 2018, 7:38 PM
Answered by Expert
Answer:
Ampere's law of magnetostatics is given by begin mathsize 12px style contour integral B times d l space equals space mu subscript 0 I end style , it means closed path integral of magnetic field B
around a conductor carrying current I is μ0 times the enclosed current, where μ0 is permeability of free space.
 
Given loop-3 consists of two loops. Right hand side loop encloses two currents of equal magnitude and in  opposite direction.
Hence net enclosed current is zero.
In left hand side, there is only one current carrying conductor. The direction of the current and direction of the magnetic field
lines are given by right-hand-rule as shown below.
when we hold the current carrying conductor in right hand as shown in figure, thumb gives the direction of current
and direction of curling of fingers gives the direction of magnetic field.
In the left side loop of loop-3 , current is downward direction.  Hence if we apply the right-hand rule,
magnetic field lines will be in clock-wise direction. But as per figure integration is performed in anti-clockwise direction.
Hence we have negative sign and begin mathsize 12px style contour integral B times d l space equals space minus mu subscript 0 I end style
Answered by Expert 21st September 2018, 6:31 AM
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