Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Sir, could you please explain how to solve this problem ? Two litres of an ideal gas at a pressure of 10 atm expands isothermally into vaccum until its total volume is 10 litres. How much heat is absorbed and how much work is done in the expansion? what would be heat absorbed and work done i.) if same expansion takes place against a constant external pressure of 1 atm? ii.) if the same expansion takes place to a final volume of 10 litres conducted reversibly?

Asked by 9th August 2012, 11:07 AM
Answered by Expert
Answer:

We have q = w = pex (10 2) = 0(8) = 0

No work is done; no heat is absorbed.

We have q = w = pex (8) = 8 litre-atm

We have q=-w=2.303X10log (10/2)=16.1latm

Answered by Expert 14th August 2012, 12:44 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!