ICSE Class 10 Answered
Sin35°sin55°-cos35°cos55°
Asked by devika.selokar1987 | 01 Jan, 2019, 10:56: PM
Expert Answer
sin(90-θ) = cosθ
sin35° × sin55° = sin(90-55)° × sin(90-35)° = cos55° × cos35°
hence, ( sin35° × sin55° - cos55° × cos35° ) = 0
Answered by Thiyagarajan K | 02 Jan, 2019, 08:44: AM
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