Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Silver crystallizes in fcc unit.Each side of the unit cell has a length of 409pm.What is the radius of silver atom ?

Asked by Pratik 10th October 2015, 12:07 PM
Answered by Expert
Answer:
Let r be the radius and a is the edge length of the unit cell.
For FCC lattice,
straight r equals fraction numerator straight a over denominator 2 square root of 2 end fraction straight r equals fraction numerator 409 over denominator 2 cross times 1.414 end fraction straight r equals 144.6 space pm
Answered by Expert 10th October 2015, 4:15 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp