Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
For Business Enquiry


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

Show that the relation R, defined in a set A of all triangles as {(T1, T2) : T1 is similar triangle to T2}, is equivalence relation.

Asked by Topperlearning User 25th October 2016, 7:54 AM
Answered by Expert

R = {(T1, T2) : T1 is similar triangle to T2}

(i) Any triangle is always similar to itself. So, .
Therefore R is reflexive.
(ii) A triangle T1 is similar to T2, then T2 will be similar to T1,
i.e., , then R is symmetric.
(iii) If T1 is similar to T2 and T2 is similar to T3, then T1 will also be similar to T3.
So, R is transitive.
Since, relation R is reflexive, symmetric and transitive, therefore the R is an equivalence relation.
Answered by Expert 25th October 2016, 9:54 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp