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CBSE Class 11-science Answered

show that the circumferance of thr bohr orbit for the hydrogen is an integral multiple of
the de-brogli wavelenth associate with the electron revolving around the orbit
Asked by patidarshm | 11 Dec, 2015, 11:43: AM
answered-by-expert Expert Answer
begin mathsize 11px style According space to space de space Broglie space equation comma space straight lambda space equals space straight h over mν space space........ left parenthesis 1 right parenthesis According space to space Bohr apostrophe straight s space theory comma space the space angular space momentum space of space an space electron space of space mass space apostrophe straight m apostrophe comma space moving space with space speed space apostrophe straight nu apostrophe space in space orbit space of space radius space apostrophe straight r apostrophe space is space an space integral space multiple space of space fraction numerator straight h over denominator 2 straight pi end fraction. Angular space momentum space equals space mνr space equals space fraction numerator nh over denominator 2 straight pi end fraction space space........ left parenthesis 2 right parenthesis or space 2 πr space equals nh over mν space equals space straight n space straight lambda space space left parenthesis From space left parenthesis 1 right parenthesis right parenthesis therefore space 2 πr space equals space straight n space straight lambda Thus comma space circumference space left parenthesis 2 πr right parenthesis space of space the space Bohr apostrophe straight s space orbit space for space the space hydrogen space atoms space is space an space integral space multiple space of space the space de space Broglie space wavelength space left parenthesis straight lambda right parenthesis. end style
Answered by Hanisha Vyas | 11 Dec, 2015, 06:38: PM
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