self inductance of an inductor coil having 100 turns is 20mH . The magnetic flux through the cross section of the coil corresponding to current of 4mH is?
Asked by imtiyazmulla68
23rd March 2018,
9:40 PM
Answered by Expert
Answer:
The required formula is L×i = N×Φ , where L is the self-inductance, i is current , N is number of turns and Φ is magnetic flux,
you are given with L, i and N. hence find Φ using the above formula
Answered by Expert
24th March 2018,
7:28 AM
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