ICSE Class 10 Answered
sec⁴A(1-sin⁴A)-2tan²A =1
Asked by jatinder324 | 10 May, 2020, 04:21: PM
Expert Answer
L.H.S = sec4A(1 - sin4A) - 2tan2A
= sec4A - sec4A sin4A - 2tan2A
= sec4A - sec4A(1/cos4A) - 2tan2A
= sec4A - tan4A - 2tan2A
= [(sec2A)2 - (tan2A)2] - 2tan2A
= (sec2A - tan2A)(sec2A + tan2A)- 2tan2A
= sec2A + tan2A - 2tan2A ..... (sec2A + tan2A = 1)
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