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CBSE Class 12-science Answered

Resistance
Asked by Sashank G | 17 Feb, 2011, 03:55: PM
answered-by-expert Expert Answer
Dear student
we know that, power =  ( Voltage)2 / resistance
In series, net resistance = 3R
Therefore (voltage)2 = power x resistance = (X) (3R) = 3XR
In parallel, net resistance = R/3
Therefore, power dissipated =  ( Voltage)2 / resistance = (3XR) / (R/3) = 9X
Hope this helps.
Regards
Team
Topperlearning
Answered by | 18 Feb, 2011, 11:52: AM
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