Ref 947
Asked by arup.isro
19th August 2018,
10:31 PM
Answered by Expert
Answer:
Figure shows the various forces acting on the cart and the force F exerted by horse.
friction force f is given by f = μN , where μ is the friction coefficient, N is the normal reaction force.
we have, f = 0.2×1500×10 = 3000 N
By newtons law for the combined system of horse and cart, we have F - f = (mC + mh )×a ..............(1)
where mC and mh are mass of cart and horse respectively and a is acceleration of the system.
by substituting the relevant values in eqn.(1), F - 3000 = (1500+500)×1 , we get F = 5000 N
Answered by Expert
20th August 2018,
2:45 PM
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