Ref 059
Asked by arup.isro
19th August 2018,
10:32 PM
Answered by Expert
Answer:
If we consider the contact force is the resultant R of Normal reaction force N and friction force f,
then as shown in figure, the angle θ made by resultant R with vertical is given by,
tanθ = (μmg) / mg = μ
we are given that frictin force f is 3 N, hence f = μ×m×g = 3 Newton , hence μ = 3/(0.4×10) = 0.75
θ = tan-1(0.75) = 37º
magnitude R = 
Answered by Expert
20th August 2018,
12:54 PM
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