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Asked by arindeep.singh | 20 Aug, 2020, 06:56: PM
answered-by-expert Expert Answer
sin2A = 2sinA
→ 2sinAcosA = 2sinA
→ 2sinAcosA - 2sinA = 0
→ 2sinA(cosA - 1) = 0
→ 2sinA  = 0 or (cosA - 1) = 0
 → sinA  = 0 or cos A= 1
→     A  = 0° or A = 0°
 
Hence, it is proved that sin2A = 2sinA when A = 0°


 

Answered by Yasmeen Khan | 20 Aug, 2020, 10:27: PM

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