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CBSE Class 12-science Answered

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Asked by tatsemsandhu3015 | 29 May, 2020, 11:34: AM
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Question: - The electric field and electric potential at any point due to a point charge kept in air is 20 NC-1 and 10 JC-1 respectively. Calculate the distance of the point from the charge and magnitude of the charge.
 
Solution: - 
E space equals space fraction numerator q over denominator 4 pi epsilon subscript 0 r squared end fraction space equals space 20 space N divided by C space V space equals space fraction numerator q over denominator 4 pi epsilon subscript 0 r end fraction space equals space 10 space J divided by C space T h u s comma space r space equals space V over E space equals space 10 over 20 space equals space 0.5 space m space T h u s comma space m a g n i t u d e space o f space c h a r g e space i s space q space space equals space open parentheses 4 pi epsilon subscript 0 close parentheses V r thin space equals space fraction numerator 1 over denominator 9 cross times 10 to the power of 9 end fraction cross times 10 cross times 0.5 space equals space 0.55 space cross times 10 to the power of negative 9 end exponent space C space
 
P.S. -Dear user, if you need answer for rest of the questions then please ask them seperately in different post as only one question can be answered in each post. 

 

Answered by Shiwani Sawant | 29 May, 2020, 12:10: PM

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