Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Home / Doubts and Solutions/CBSE/Class 11 Commerce/Mathematics

Question no. 14

qsnImg
Asked by Payal 21st February 2018, 4:57 PM
Answered by Expert
Answer:
begin mathsize 16px style According space to space the space question space 1 comma 2 comma 3 comma.... straight p space and space common space ratios space 1 half comma 1 third comma 1 fourth.... comma fraction numerator 1 over denominator straight p plus 1 end fraction Sum space of space infinite space GP space equals fraction numerator straight a over denominator 1 minus straight r end fraction Find space straight S subscript 1 comma straight S subscript 2...... straight S subscript straight p you space get straight S subscript 1 space equals 2 comma space straight S subscript 2 space equals 3 comma....... comma straight S subscript straight p equals straight p plus 1 From space this space we space can space observe space that space sums space are space in space AP space with space straight a equals 2 space and space straight d equals 1 straight p over 2 open square brackets 2 cross times 2 plus open parentheses straight p minus 1 close parentheses cross times 1 close square brackets equals fraction numerator straight p left parenthesis straight p plus 3 right parenthesis over denominator 2 end fraction end style
Answered by Expert 21st February 2018, 5:23 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: sum-of-infinite-gp sum-of-series geometric-progression
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

Show that the ration of sum of first n terms of a GP tto sum of terms from (n+1)th term to 2n th term is 1/r^n
15th January 2018, 9:55 AM
If a,b,c,d are in consecutive terms of GP prove that (a^2+b^2) +(b^2+c^2) +(c^2 +d^2) are in g.p
23rd February 2018, 5:10 PM
Find five geometric means between 1 and 27.
23rd February 2018, 4:54 PM
If a,b,c are in continued proportion ,prove that (a+b+c) (a-b-c) = a^2+b^2+c^2  
23rd February 2018, 6:49 PM
  700002544_Topper_2_110_ ... 649_1516706377_4175.pdf (Topper learning's most important questions maths ) chapter11 question 3   
25th February 2018, 11:35 AM
RELATED STUDY RESOURCES :
CBSE Class-11-commerce QUESTION ANSWERS

Chat with us on WhatsApp