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CBSE Class 11-commerce Answered

Question no. 14
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Asked by Payal | 21 Feb, 2018, 04:57: PM
answered-by-expert Expert Answer
begin mathsize 16px style According space to space the space question space 1 comma 2 comma 3 comma.... straight p space and space common space ratios space 1 half comma 1 third comma 1 fourth.... comma fraction numerator 1 over denominator straight p plus 1 end fraction Sum space of space infinite space GP space equals fraction numerator straight a over denominator 1 minus straight r end fraction Find space straight S subscript 1 comma straight S subscript 2...... straight S subscript straight p you space get straight S subscript 1 space equals 2 comma space straight S subscript 2 space equals 3 comma....... comma straight S subscript straight p equals straight p plus 1 From space this space we space can space observe space that space sums space are space in space AP space with space straight a equals 2 space and space straight d equals 1 straight p over 2 open square brackets 2 cross times 2 plus open parentheses straight p minus 1 close parentheses cross times 1 close square brackets equals fraction numerator straight p left parenthesis straight p plus 3 right parenthesis over denominator 2 end fraction end style
Answered by Sneha shidid | 21 Feb, 2018, 05:23: PM

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CBSE 11-commerce - Maths
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