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CBSE Class 11-science Answered

question is attached. Please send step by step complete solution.
Asked by sudhanshubhushanroy | 10 Dec, 2017, 04:09: AM
answered-by-expert Expert Answer
begin mathsize 16px style let space straight a space and space straight b space be space the space two space numbers space straight b greater than straight a comma
AM greater or equal than GM
fraction numerator straight a plus straight b over denominator 2 end fraction equals 2
straight a plus straight b equals 4..... left parenthesis 1 right parenthesis
fraction numerator straight a plus straight b over denominator 2 end fraction equals square root of straight a open parentheses straight b plus 1 close parentheses end root
square
4 equals ab plus straight a...... left parenthesis 2 right parenthesis
from space left parenthesis 1 right parenthesis space & space left parenthesis 2 right parenthesis
straight a equals 4 space or space straight a equals 1
now space straight a equals 4 space then space straight b equals 0
so space straight a equals 1 space straight b equals 3
HM equals fraction numerator 2 ab over denominator straight a plus straight b end fraction


end style
Answered by Arun | 10 Dec, 2017, 04:48: PM
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