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CBSE Class 9 Answered

Question Factorise: x3 + 13x2 + 32x + 20 Solution: Let p(x) = x3 + 13x2 + 32x + 20 p(-1) = -1 + 13 - 32 + 20 = -33 + 33 = 0 Therefore (x + 1) is a factor of p(x). On dividing p(x) by (x + 1) we get p(x)   (x + 1) = x2 + 12x + 20 Thus, x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20) = (x + 1) (x2 + 10x + 2x + 20) = (x + 1)[x(x + 10) + 2(x + 10)] = (x + 1) (x +2) (x + 10) Hence, x3 + 13x2 + 32x + 20 = (x + 1) (x +2) (x + 10). The above question is from the sureshot questions but I am not clear with the explanation.Please elaborate.Please reply urgently I have my Maths exam tomorrow
Asked by nayonika.online.learning | 17 May, 2018, 09:08: PM
answered-by-expert Expert Answer
Factor theorem is used here
 p(x) = x3 + 13x2 + 32x + 20
start by sub x= 1,-1,.... to get p(x)=0
now
p(-1) = -1 + 13 - 32 + 20 = -33 + 33 = 0
so x+1 is a factor......factor theorem
now divide x3 + 13x2 + 32x + 20 by x+1......long division
you will get remainder zero, and quotient =x2 + 12x + 20
so,
Divident =divisor x quotient +remainder
x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20)......factorize x2 + 12x + 20 by spliting middle term
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