Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

CBSE - X - Physics - Electricity


Asked by sweetynam 18th February 2009, 4:32 PM
Answered by Expert



Resistance when 10 bulbs are in parallel,R||=R/10

Resistance when 10 bulbs are in series,Rseries=10R

Voltage acros each bulb in first case is V while in second case is V/10. So first circuit has highest voltage across each bulb. But current in second circuit across each bulb is 10 times that flowing across each blb in first case. So 

power dissipated is more in second case per bulb. Thus bulbs brighten more in second case.

Answered by Expert 20th February 2009, 5:22 PM

Rate this answer

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Your answer has been posted successfully!