CBSE Class 11-science Answered
Question - 4 :
A block a frictionless pulley and to its other end another block B of mass m2 = 3 kg is fastened of mass m1 = 20 kg rests on a horizontal table. A light string connected to it passes over. The coefficient of kinetic friction between the block and the table is k = 0.04. The block A is sliding on the table. Calculate the acceleration of each block and the tension in the string. Take g = 10 m/s^2.
Asked by sudhanshubhushanroy | 25 Feb, 2018, 04:26: PM
Expert Answer
Tension in the string is due to the gravitiational force geiven by the 3 kg block. Hension Tension in the string = 3×10 = 30 N
Net force acting on block = 3g-0.8g = 2.2g = 2.2×10 = 22 N
hence acceleration of each block = 22/20 = 1.1 m/s2 . acceleration is common for both the block
Answered by Thiyagarajan K | 26 Feb, 2018, 12:58: PM
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