Question - 3 :
A train is moving with a speed of 72 km/h on a curved railway line of 400 m radius. A spring balance loaded with a block of 5 kg is suspended from the roof of the train.
(i) What would be the reading of the balance ?
(ii) If, in the above case, the spring makes an angle of 10 degree with the vertical, then what is the centripetal acceleration of the train ? ( g = 10 m/s^2, Tan 10 degree = 0.176 ).
Asked by sudhanshubhushanroy
25th February 2018,
4:19 PM
Answered by Expert
Answer:
5 kg block is subjected to two forces due to gravity, i.e. 50 N and centripetal force (mv2)/R = 5 N.
(train speed 72 km/hr = 20 m/s )
hence resultant is 
hence Spring balance reading 50.25 / 10 = 5.025 kg
if spring balance makes an angle θ means, resultant force is at angle θ
by substituting for R and g, we get speed 26.55 m/s, corresponds to 95.6 km/hr
Answered by Expert
26th February 2018,
9:06 AM
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