Question - 1 :
A stream of water flowing horizontally with a speed of 15 m/s gashes out of a tube of cross sectional area 10^-2 m^2 and hits a nearby vertical wall. Find the force exerted on the wall by the impact of water. Assume that water does not rebound from the wall. Take density of water to be 1 X 10^3 kg m^-3.
Asked by sudhanshubhushanroy
25th February 2018,
4:16 PM
Answered by Expert
Answer:
Force exerted by the wall due to water jet = 
where ρ is density of water, v is the speed of water and A area of cross section of the hose pipe.
force = 0.5×1000×15×15×0.01 = 1125 N
Answered by Expert
26th February 2018,
8:07 AM
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