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Home / Doubts and Solutions/JEE/Physics

ques9

Asked by rbhatt16 28th December 2017, 11:47 AM
Answered by Expert
Answer:
begin mathsize 20px style f r o m space P a s c a l apostrophe s space l a w space P subscript 0 equals P subscript 0 space plus rho subscript a g h subscript a space minus space rho subscript b g h subscript b space plus rho subscript c g h subscript c space minus space rho subscript d g h subscript d space a equals c equals 95 to the power of ring operator space C b equals d equals 5 to the power of ring operator space C 0 equals space rho subscript a g space left parenthesis 52.8 right parenthesis space minus space rho subscript b g space left parenthesis 49 right parenthesis space plus space space rho subscript c g space left parenthesis 49 right parenthesis space minus space rho subscript d g space left parenthesis 51 right parenthesis rho subscript 5 to the power of o C end subscript over rho subscript 95 to the power of o C end subscript equals fraction numerator 52.8 plus 49 over denominator 48 plus 51 end fraction equals 1.08 gamma equals space c o e f f i c i e n t space o f space V o l u m e space e x p a n s i o n equals fraction numerator V subscript 95 minus V subscript 5 over denominator V subscript 5 left parenthesis 95 minus 5 right parenthesis end fraction equals fraction numerator rho subscript 5 minus rho subscript 95 over denominator rho subscript 95 x space 90 end fraction equals 2 x 10 to the power of negative 4 end exponent space divided by to the power of o C C o e f f i c i e n t space o f space l i n e a r space e x p a n s i o n space equals space gamma over 3 equals 6.7 space x space 10 to the power of negative 5 end exponent space space divided by to the power of o C end style
Answered by Expert 28th December 2017, 3:27 PM
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