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Home / Doubts and Solutions/JEE/Physics

ques5

Asked by rbhatt16 20th December 2017, 11:55 PM
Answered by Expert
Answer:
breaking stress given in this question is very small (8 ×106 N/m2). Typical data for steel wire is 1.2 × 109 N/m2. So breaking stress assumed to solve this question is 1,0 × 109 N/m2
if m1 = 10 kg, m2 = 20 kg, T1 = (10+w)g, T2 = (30+w)g;
 
begin mathsize 12px style T subscript 1 over A subscript 1 space equals space B r e a k i n g space s t r e s s space o f space w i r e space b e t w e e n space m subscript 1 space a n d space m subscript 2 A subscript 1 space i s space a r e a space o f space c r o s s space s e c t i o n space equals space 0.003 space c m squared fraction numerator open parentheses 10 plus W close parentheses begin display style cross times end style begin display style 9 end style begin display style. end style begin display style 8 end style over denominator 3 cross times 10 to the power of negative 7 end exponent end fraction equals space 10 to the power of 9 end style

 
Solving the above equation for W, we will get W = 20.61 kg
begin mathsize 12px style T subscript 2 over A subscript 2 space equals space B r e a k i n g space s t r e s s space o f space w i r e space b e t w e e n space M subscript 2 n space a n d space s u p p o r t fraction numerator open parentheses 30 plus w close parentheses begin display style cross times end style begin display style 9 end style begin display style. end style begin display style 8 end style over denominator 6 cross times 10 to the power of negative 7 end exponent end fraction equals 10 to the power of 9 end style
solving the above equationfor W, we will get W = 31.22 kg
 
maximum load 20.61 kg, the wire between m1 and m2 will break first.
 
The student should repeatation part of the question in same way
Answered by Expert 23rd December 2017, 5:06 PM
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