Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Ques2

qsnImg
Asked by rbhatt16 19th July 2018, 9:24 AM
Answered by Expert
Answer:
Angular momentum L of a particle of mass m moving in a circular orbit of radius a is given by,
 
L = m×v×a ............(1)
 
when electron moves in a magnetic field B, we have   B×e×v = m×v2 /a  or  e×B×a = m×v .........(2)
 
from (1) and (2), we can write L = e×B×a2
Answered by Expert 20th July 2018, 3:59 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp