Ques11
Asked by rbhatt16
14th July 2018,
9:57 PM
Answered by Expert
Answer:
Figure given above illustrates the informations given in the question.
Using polar coordinate system we can calculate the width d of field region as
d = R sin60 - R sin 30 = R[ (√3/2) - (1/2)] .......(1)
we know in magnetic field region a charge of q Coulomb moves in a circular path and force acting on the charge is q×B×v,
where B is magnetic field strength and v is speed of charge.
hence we have 
from (1) and (2), we have 
Answered by Expert
16th July 2018,
12:17 PM
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