 Contact

For Enquiry

10:00 AM to 7:00 PM IST all days.

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

8788563422

Mon to Sat - 10 AM to 7 PM

# Ques no 64 Asked by chandanbr6004 26th November 2017, 10:19 AM Force balance: -  mg = R1+µR2

Normal force R2 is unbalanced and makes the sphere to move right to left.

Torque due to the friction force µR2 retarding the circular motion.

Hence µR2×r = I α = (2/5) mr2×α ……………………………(1)

I is Mom. Of Inertia and α is angular retardation

Substitute for µ( µ = 1/5 )and simplify to get

R2 = 2mrα …………………………………………………………(2)

Let the unbalanced horizontal force R2 changes the linear velocity from v to V during the contact time t

Then R2 = m(V-v)/t………………………………………..(3)

From (2)and (3)  m(V-v)/t = -2mrα

Negative sign on RHS is due to retardation

After simplification we get   (V-v) = -2rαt……………(4)

If initial angular velocity is ω and if angular velocity is zero after contact time t, then we can write

0 = ω – αt or ω = αt

Substitute for αt in equation (4) to get (V-v) = -2rω = -2v

Hence V = -v (negative sign indicates sphere moving from right to left)

If we take the magnitude of velocity immediately after collision, |V| = v

Answered by Expert 30th November 2017, 2:48 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

RELATED STUDY RESOURCES :

### Latest Questions

ICSE X Physics Refraction of Light at Plane Surfaces Asked by nilesh.dhote74 3rd June 2020, 9:25 PM
ICSE X Physics Refraction of Light at Plane Surfaces Asked by nilesh.dhote74 3rd June 2020, 9:18 PM
ICSE X Physics Refraction of Light at Plane Surfaces Asked by nilesh.dhote74 3rd June 2020, 9:16 PM