ques no 41
ques no 41
Asked by chandanbr6004
26th November 2017,
10:24 AM
Answered by Expert
Answer:
Let us consider small area of half disc as shown in figure whose radius is r and width dr.
mass of this shaded portion, m = ρ × Π × r × dr
where ρ is mass per unit area.
moment of inertia of this shaded area of disc about the axis passing through the centre of disc is mr2 = ρ × Π × r × dr × r2
Hence moment of inertia of whole disc is given by
mass of the given disc M is 
Hence 
Answered by Expert
27th November 2017,
2:54 PM
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