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Home / Doubts and Solutions/JEE/Physics

ques no 10

Asked by chandanbr6004 15th November 2017, 9:40 PM
Answered by Expert
Answer:
Initially both the masses and centre of mass are at height H.
If only mass m is dropped (keeping mass M at height H ) it will bring the centre of mass at height less than H
If only mass M is projected upward (keeping mass m at height H ) the centre of mass will shift upward at height more than H
 
But here are both are projected simultaneouly
 
Only Mass is responsible to shift centre of mass in the upward direction.
 
velocity of centre of mass due to mass M
 
u=Mu/(m+M)
 
height attained by mass M with this velocity = u2/2g
 
equals fraction numerator begin display style open parentheses fraction numerator begin display style M u end style over denominator begin display style m plus M end style end fraction close parentheses squared end style over denominator 2 g end fraction equals fraction numerator 1 over denominator 2 g end fraction open parentheses fraction numerator begin display style M u end style over denominator begin display style m plus M end style end fraction close parentheses squared
 
 
since m has not reached ground centre of mass would be around the height H due to upward motion of M
 
 
therefore total height = H + height gained by M
 
 
equals H plus fraction numerator 1 over denominator 2 g end fraction open parentheses fraction numerator begin display style M u end style over denominator begin display style m plus M end style end fraction close parentheses squared
 
Answered by Expert 7th December 2017, 1:46 PM
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