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Home / Doubts and Solutions/JEE/Mathematics

ques 25

Asked by chandanbr6004 26th November 2017, 1:20 PM
Answered by Expert
Answer:
begin mathsize 16px style 2 straight C subscript 0 plus fraction numerator 2 squared straight C subscript 1 over denominator 2 end fraction plus fraction numerator 2 cubed straight C subscript 2 over denominator 3 end fraction plus..... plus fraction numerator 2 to the power of straight n plus 1 end exponent straight C subscript straight n over denominator straight n plus 1 end fraction left parenthesis 1 plus straight x right parenthesis to the power of straight n equals straight C subscript 0 plus straight C subscript 1 straight x plus straight C subscript 2 straight x squared plus.... plus straight C subscript straight n straight x to the power of straight n Integrate space on space both space sides space from space straight x equals 0 space to space straight x equals 2 We space get space 2 straight C subscript 0 plus fraction numerator 2 squared straight C subscript 1 over denominator 2 end fraction plus fraction numerator 2 cubed straight C subscript 2 over denominator 3 end fraction plus..... plus fraction numerator 2 to the power of straight n plus 1 end exponent straight C subscript straight n over denominator straight n plus 1 end fraction equals fraction numerator 3 to the power of straight n plus 1 end exponent minus 1 over denominator straight n plus 1 end fraction end style
Answered by Expert 28th November 2017, 11:58 AM
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