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Home / Doubts and Solutions/JEE/Physics

ques 12

Asked by rbhatt16 11th November 2017, 9:46 PM
Answered by Expert
Answer:
 
Let the particle strike the plane AP’ at time t after the initial projection time and let it strike at P.
 
The angluar displacement made by the plane is (β-ωt). 
 
The horizontal distance travelled = L + l × cos(β-ωt).
 
The time t will be obtained by dividing the horizontal distance by horizontal velocity.
 
t = ( L +  l × cos(β-ωt) ) / ( v0 cosθ )
 
Vertical distance  is given by
l × sin(β-ωt) = v0 sinθ × t - (1/2) × g  × t2 
 
velocity of the particle w.r.t point of impact just before striking is given by
 

Answered by Expert 13th November 2017, 5:11 PM
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