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Home / Doubts and Solutions/JEE/Chemistry

ques 12

Asked by rbhatt16 12th November 2017, 10:16 PM
Answered by Expert
Answer:
space space because space L i C l.3 N H subscript 3 space end subscript subscript left parenthesis s right parenthesis space end subscript space leftwards arrow over rightwards arrow with blank on top L i C i. N H subscript 3 subscript left parenthesis s right parenthesis end subscript space plus 2 N H subscript 3 left parenthesis g right parenthesis end subscript space space...... space left square bracket K p equals 9 a t m to the power of 2 space end exponent right square bracket space space space space space space space space space space space space space space space space space space space space space space space space space space space space space therefore space L i C l. N H subscript 3 left parenthesis s right parenthesis space end subscript plus space 2 N H subscript 3 left parenthesis g right parenthesis space end subscript leftwards arrow over rightwards arrow with blank on top space L i C l. N H subscript 3 left parenthesis s right parenthesis end subscript space space space space space..... left square bracket K p space equals space 1 over 9 a t m to the power of negative 2 end exponent I n i t i a l space m o l e space space space space space space space space space space space space space space space space space space space space space space 0.1 space space space space space space space space space space space space space space space a space space space space space space space space space space space space space space space space space space space space space 0 f i n a l space m o l e space a t space e q to the power of m space space space end exponent space space space space space space space space space space space space space 0 space space space space space space space space space space space space left parenthesis a minus 0.2 right parenthesis space space space space space space space space space space space space space space space 0.1 space space space l e t space i n i t i a l space m o l e space o f space N H subscript 3 space end subscript s h o u l d space b e space space a space t o space b r i n g space i n space c o m p l e t i o n space o f space r e a c t i o n. A t space e q to the power of m space end exponent space K p subscript 1 space end subscript equals fraction numerator 1 over denominator left parenthesis P apostrophe N H subscript 3 right parenthesis squared end fraction space space space o r space space space space 1 over 9 equals fraction numerator 1 over denominator left parenthesis P apostrophe subscript N H subscript 3 end subscript right parenthesis squared end fraction space space h e n c e comma space therefore P apostrophe subscript N H subscript 3 end subscript space equals square root of 9 space space space space space space space space space space space space space space space space therefore P apostrophe subscript N H subscript 3 end subscript space equals space 3 space a t m space space space space space space space space space space space space space space space space because space P V space equals space n R T space space space space space space space space space space space space space space space space space 3 cross times 5 space equals space n space cross times 0.0821 cross times 313 space space space space space space space space space space space space space space space space space space space space space space n space equals space 0.5837 i. e. comma space left parenthesis a minus 0.2 right parenthesis space equals space 0.5837 space space space space space space space therefore space I n i t i a l space m o l e space o f space N H subscript 3 space equals space a equals space 0.5837 space plus space 0.2 space space equals space 0.7837 space m o l e
Answered by Expert 13th November 2017, 11:41 AM
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