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ques 12 and 13

Asked by rbhatt16 12th October 2017, 5:18 PM
Answered by Expert
Answer:
begin mathsize 16px style According space to space the space question
fraction numerator 1 over denominator straight a subscript 1 space end fraction comma 1 over straight a subscript 2 comma 1 over straight a subscript 3 comma........... space are space in space AP

1 over straight a subscript 2 minus fraction numerator 1 over denominator straight a subscript 1 space end fraction space equals space straight d
straight d space equals space fraction numerator straight a subscript 1 space minus straight a subscript 2 space over denominator straight a subscript 1 straight a subscript 2 end fraction
straight a subscript 1 straight a subscript 2 space equals fraction numerator straight a subscript 1 space minus straight a subscript 2 space space over denominator straight d end fraction
Similarly space you space can space find space out space for space straight a subscript 2 space straight a subscript 3 space comma space straight a subscript 3 space straight a subscript 4 comma.....
fraction numerator 1 over denominator straight a subscript straight n space end fraction equals 1 over straight a subscript 1 space plus space left parenthesis straight n minus 1 right parenthesis space straight d
on space simplifying space we space get
fraction numerator straight a subscript 1 space minus space straight a subscript straight n over denominator straight d end fraction space equals space left parenthesis straight n space minus 1 right parenthesis straight a subscript 1 space straight a subscript straight n
Substitute space it space in space LHS space and space simplify space it space further. end style
Answered by Expert 19th December 2017, 5:38 PM
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