Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

quadrilateral
Asked by | 13 Feb, 2009, 10:28: PM
answered-by-expert Expert Answer

The sum of the zeroes of a polynomial  in x =-b/a

and

 the product of the zeroes=c/a

 where

 a is coefficient of x squared and b is coefficient of the  term in x and c is the term free of x.

So, here,

a=1, b=-8 and c=k

So sum of the zeroes = -b/a= -(-8)/1=8

product of the zeroes=c/a=k

We need to find the sum of squares of the zeroes.

Answered by | 14 Feb, 2009, 08:46: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by 2806rahul | 30 May, 2010, 09:28: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 11:59: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×