CBSE Class 11-science Answered
Quadratic Equations
Asked by | 29 Sep, 2009, 09:55: AM
Expert Answer
Deare Student
x^2+ax+b=0
Roots of the above quadratic equation x1, x2= [-a +/- 
(a2-4b) ] / 2= -a/2 +/- [ (a2-4b)]/2
==> x1+x2= -a and it is given that |x1|=|x2|=1 ==> |x1|+|x2|=2 ==> a
2
y^2+|a|y+b=0 in case of this equation !a! 2.
Regards
Topperlearning
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