JEE Class main Answered
Q.Solve the question in photo
Asked by Vidushi412 | 24 Mar, 2019, 10:57: AM
Expert Answer
a3 +b3 = (a+b) [ a2 +ab +b2 ] hence ( a3 +b3 ) / (a+b) = a2 +ab +b2
a5 + b5 = (a+b) [ a4 +a3b +a2b2 +ab3 +b4 ] hence ( a5 + b5 ) / (a+b) = a4 +a3b +a2b2 +ab3 +b4 ]
similarly if n is odd, ( an + bn ) / (a+b) = an-1 + an-2 b +an-3 b2 +..........+a bn-2 + bn-1
hence ( an + bn ) is divisible by (a+b) if n is odd
Answered by Thiyagarajan K | 24 Mar, 2019, 10:17: PM
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