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Q5 in the attached picture.Please help.I am getting any clear concept from this question.

qsnImg
Asked by Sanjeev 20th February 2018, 10:05 PM
Answered by Expert
Answer:
begin mathsize 16px style Given colon space
straight I space is space the space incentrte space of space straight a space circle comma space angle straight P equals 70 degree comma space angle PQR equals 54 degree
Find colon space
angle SPR comma space angle IPR comma space angle SIR
Proof colon
angle straight P equals 70 degree
angle IPQ equals angle IPR space space space space space space space space space space space space space space space space space space space space space PI space is space angle space bisector space of space angle IPQ space and space angle IPR
angle IPR equals 35 degree
angle SPR plus angle RPI plus angle IPQ equals 70 degree
angle PQR equals 54 degree
angle PQS equals angle RQS equals 27 degree space space space space space space space space space space space space space space space space space QI space is space bisector space of space angle straight Q
Arc space space SR equals 27 degree cross times 2 equals 54 degree
angle SPR equals fraction numerator arc space SR over denominator 2 end fraction equals 27 degree
angle SIR equals fraction numerator arc space SR over denominator 2 end fraction equals 27 degree








end style
Answered by Expert 21st February 2018, 5:13 PM
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