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CBSE - IX - Mathematics

q26

Asked by 1st September 2009, 7:01 PM
Answered by Expert

Answer:

log V + log 3 = log(22/7) + log 4 + 3 log r

log 3V = log (22/7)(4) + 3 log r

log 3V = log (22/7)(4) +  log r3

log 3V = log (22x4xr3/7)

Taking antilog,

 3V = 22x4xr3/7

 V = 22x4xr3/(7x3)

Regards,

Team,

TopperLearning.

Answered by Expert 1st September 2009, 11:50 PM

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