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CBSE Class 9 Answered

Q.1.If 2m+n divided by 2n-m = 16 and a = 21/10 , then a2m+n-p divided by (am-2n+2p )-1 =

       

Asked by Shreshth Sahu | 23 May, 2014, 07:48: PM
answered-by-expert Expert Answer
G i v e n space t h a t space 2 to the power of m plus n end exponent over 2 to the power of n minus m end exponent equals 16 rightwards double arrow 2 to the power of m plus n minus n plus m end exponent equals 2 to the power of 4 rightwards double arrow 2 to the power of 2 m end exponent equals 2 to the power of 4 rightwards double arrow 2 m equals 4 rightwards double arrow m equals 2 A l s o space g i v e n space t h a t space a equals 2 to the power of 1 over 10 end exponent W e space n e e d space t o space f i n d space t h e space v a l u e space o f space a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent : T h u s comma space w e space h a v e comma a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent equals a to the power of 2 m plus n minus p end exponent cross times a to the power of m minus 2 n plus 2 p end exponent rightwards double arrow a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent equals a to the power of 2 m plus m plus n minus 2 n minus p plus 2 p end exponent rightwards double arrow a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent equals a to the power of 3 m minus n plus p end exponent rightwards double arrow a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent equals open parentheses 2 to the power of 1 over 10 end exponent close parentheses to the power of 3 m minus n plus p end exponent rightwards double arrow a to the power of 2 m plus n minus p end exponent over open parentheses a to the power of m minus 2 n plus 2 p end exponent close parentheses to the power of minus 1 end exponent equals open parentheses 2 to the power of 1 over 10 end exponent close parentheses to the power of 6 minus n plus p end exponent
Please check your question.
Without knowing the values of n and p, it is difficult find the value of the required expression.
Answered by Vimala Ramamurthy | 27 May, 2014, 10:35: AM

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