Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

9321924448

Mon to Sat - 10 AM to 7 PM

# Q1

Asked by MUKUL 4th October 2019, 7:42 PM
EMF induced in the loop , E = - (dΦ/dt) = - A (dB/dt)  ......................(1)

where Φ is magnetic flux. Magnetic flux = B×A , where B is magnetic flux density and A is area of loop.

Magnetic Flux density B at centre of loop due to current Io passing through wire is given by,

...........................(2)
using eqn.(1) and (2), EMF induced in loop,

Current I in the loop is obtained by dividing the induced emf by resistance of the loop and it is given by,

Force between the induced current and current passing through long wire is given by

In the above equation to get Force, dIo is considered as dIo = ( Io - 0 ) = Io

Acceleration a' is obtained by dividing force F by mass m

a' =
velocity v of loop after time dt staring from rest is  given by

Answered by Expert 4th October 2019, 9:37 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10