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CBSE Class 11-science Answered

Q.
Asked by imabhi264 | 11 Aug, 2017, 09:49: PM
answered-by-expert Expert Answer
The following steps need to be followed to solve such dimensions related queries:
 
1) Take the dimension of the quantity on the left. [t] = [T]
 
2) Establish the relation between LHS and RHS. begin mathsize 12px style straight t proportional to straight h to the power of straight x straight rho to the power of straight y straight g to the power of straight z rightwards double arrow straight t equals straight k straight h to the power of straight x straight rho to the power of straight y straight g to the power of straight z end style
 
3) Find the dimension of all the quantities on the right. h, ρ and g = [h] = [L]; [ρ] = [ML-3]; [g] = [LT-2].
 
4) Use the relation in step 2 and the dimensions in step 3 to find the values of x, y and z. [T] = [L]x [ML-3]y [LT-2]z
 
5) Match the dimensions of LHS and RHS. You will get x = 1/2; y = 0; z = -1/2. Your final relation will be t = k√h/g
Answered by Romal Bhansali | 14 Aug, 2017, 02:28: PM

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