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CBSE Class 10 Answered

Q no 90  
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Asked by aryang9020 | 29 Jan, 2019, 01:19: PM
answered-by-expert Expert Answer
i = 4.8 A
n is number of electrons flowing through cross section per second
 
n = n x 1019 
e = 1.6 x 10-19 C 
t = 1 s 
 
We know, 
 
i italic space italic equals italic space fraction numerator n italic space e over denominator t end fraction italic 4 italic. italic 8 italic space italic equals italic space fraction numerator n italic space italic cross times italic space italic 10 to the power of italic 19 italic space italic cross times italic space italic 1 italic. italic 6 italic space italic cross times italic 10 to the power of italic minus italic space italic 19 end exponent over denominator italic 1 end fraction italic rightwards double arrow italic space n italic space italic equals italic space fraction numerator italic 4 italic. italic 8 over denominator italic 1 italic. italic 6 end fraction italic space italic equals italic space italic 3
Answered by Shiwani Sawant | 29 Jan, 2019, 06:28: PM

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