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Q

Asked by Arushi Juyal 16th December 2017, 7:09 AM
Answered by Expert
Answer:
space space space space space space space space 1 over straight lambda space equals space straight R open parentheses 1 over straight n squared minus 1 over straight n subscript 2 squared close parentheses

space fraction numerator 1 over denominator begin display style bevelled fraction numerator 16 over denominator 15 straight R end fraction end style end fraction space equals space space straight R open parentheses fraction numerator begin display style 1 end style over denominator begin display style 1 squared end style end fraction minus fraction numerator begin display style 1 end style over denominator begin display style straight n subscript 2 squared end style end fraction close parentheses

fraction numerator 15 straight R over denominator 16 end fraction space equals space straight R open parentheses fraction numerator straight n subscript 2 squared minus 1 over denominator straight n subscript 2 squared end fraction close parentheses

15 straight n subscript 2 squared space equals space 16 open parentheses straight n subscript 2 squared minus 1 close parentheses

15 straight n subscript 2 squared space equals space 16 straight n subscript 2 squared minus 16

space space straight n subscript 2 squared space space equals space 16

space space space space straight n subscript 2 equals space 4
Answered by Expert 16th December 2017, 3:46 PM
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