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CBSE Class 11-science Answered

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Asked by araima2001 | 18 Oct, 2016, 11:26: PM
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Equation space of space the space circle space with space radius space 3 space iand space passing space through space origin space straight s space straight x squared plus straight y squared equals 9 As space circle space touches space straight x minus axis space its space straight y space cordinate space of space the space centre space is space shifted space up space by space 3 space units. space Also space it space intersects space the space paraboal space straight y squared space equals space 4 straight x space so space the space circle space lies space in space first space quadrant. Now space it space intersects space the space parabola space at space the space diametric space end space points space means space the space space straight x minus coordinate space and space straight y minus coordinate space of space the space centre space are space same. So space the space equation space of space the space circle space is space comma left parenthesis straight x minus 3 right parenthesis squared plus left parenthesis straight y minus 3 right parenthesis squared equals 9 Now space substitute space straight y squared equals 4 straight x space in space left parenthesis straight x minus 3 right parenthesis squared plus left parenthesis straight y minus 3 right parenthesis squared equals 9 space and space find space the space points space of space intersection. Then space using space slope space fomula space for space two space poits space get space slope Slope equals fraction numerator straight y subscript 2 minus straight y subscript 1 over denominator straight x subscript 2 minus straight x subscript 1 end fraction
Answered by Vijaykumar Wani | 20 Oct, 2016, 12:56: PM

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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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