Q) How many AP's with 10 terms are there whose first terms are in the set {1,2,3} and whose common difference is in the set {1,2,3,4,5}.
Asked by Anish
29th November 2018,
11:34 AM
Answered by Expert
Answer:
Set of first term = { 1, 2, 3 }
Set of Common difference = ( 1, 2, 3, 4, 5 }
For each first term, we can make 5 number of AP using the 5 different common difference.
Hence total number of A.P = 3×5 = 15
Answered by Expert
30th November 2018,
5:31 AM
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