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Q)

Asked by araima2001 15th February 2017, 11:49 AM
Answered by Expert
Answer:
begin mathsize 16px style Adding space the space two space equations space space straight x plus straight y equals vertical line straight a vertical line space and space ax minus straight y equals 1 space we space get comma
straight x plus ax equals vertical line straight a vertical line plus 1
rightwards double arrow straight x left parenthesis 1 plus straight a right parenthesis equals vertical line straight a vertical line plus 1
rightwards double arrow straight x equals fraction numerator vertical line straight a vertical line plus 1 over denominator straight a plus 1 end fraction
Substituting space the space value space of space straight x space in space straight x plus straight y equals vertical line straight a vertical line comma space we space get
open parentheses fraction numerator vertical line straight a vertical line plus 1 over denominator straight a plus 1 end fraction close parentheses plus straight y equals vertical line straight a vertical line
rightwards double arrow straight y equals vertical line straight a vertical line minus open parentheses fraction numerator vertical line straight a vertical line plus 1 over denominator straight a plus 1 end fraction close parentheses
rightwards double arrow straight y equals fraction numerator straight a vertical line straight a vertical line plus vertical line straight a vertical line minus vertical line straight a vertical line minus 1 over denominator straight a plus 1 end fraction
rightwards double arrow straight y equals fraction numerator straight a vertical line straight a vertical line minus 1 over denominator straight a plus 1 end fraction
Given space that space the space rays space are space in space the space first space quadrant space intersect space eachother space in space the space interval space straight a element of left parenthesis straight a subscript 0 comma infinity right parenthesis
straight x equals fraction numerator vertical line straight a vertical line plus 1 over denominator straight a plus 1 end fraction greater than 0 space and space straight y equals fraction numerator straight a vertical line straight a vertical line minus 1 over denominator straight a plus 1 end fraction greater than 0 space when space space straight a greater than 1
Since space straight a element of left parenthesis straight a subscript 0 comma infinity right parenthesis comma space so space straight a subscript 0 equals 1 space end style
Answered by Expert 15th February 2017, 3:28 PM
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