Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM


Asked by Arushi Juyal 18th March 2018, 10:56 PM
Answered by Expert
One way to formulate the electronis structure of B2H6 arises from the realization that B2H6 is isoelectronic with C2H4. we can Imagine the following hypothetical reaction :
B2H42-   + 2H+ →  B2H6
because B2H42- is isoelectronic with C2H4, we can describe its electronic structure in terms of the bent bond model. we then predict that one proton would attack the bent bond below the B2H42-  plane and the other would attack the bent bond above the B2H42-  plane 
In this model each boron atom uses sp2 hybrid orbitals to bond the two terminal hydrogen atoms. The bridging atoms are involved in three center two electron bonds.
Please refer image attached.
Answered by Expert 19th March 2018, 12:37 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Latest Questions

ICSE VIII Mathematics
Asked by akhtaransarijsr 21st October 2018, 1:20 AM
CBSE XII Science Mathematics
Asked by haroonrashidgkp 20th October 2018, 11:04 PM

Chat with us on WhatsApp