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Asked by 30th July 2012, 3:42 PM
Answered by Expert
Answer:

LHS = tanA +[ [tanA+sqrt3] / [1-{(sqrt3)tanA)}] ] +[ [tanA-sqrt3] / [1+[sqrt3}tanA ] ]

           = tanA + [8tanA /(1-3tan2A)]

           = 9tanA-3tan3A / [1-3tan2A]

           = 3tan3A = RHS

Answered by Expert 30th July 2012, 4:25 PM
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