CBSE Class 11-science Answered
prove the inequalities (n!)^2
Asked by paritosh jain | 08 Aug, 2012, 10:57: AM
Expert Answer
(2n)! = (1.2.3.... n) (n + 1) (n + 2) ... (2n - 1) (2n)
> (n!) . nn [Since, (n + r) > n for r = 1, 2, 3, ... n]
Therefore, (n!) . nn < (2n)! (A)
Also, (n!)2 = (1.2.3.... n) n! <_ nn . (n!) (B)
[Since, r is less than equal to n for each r = 1, 2, 3 , ... n]
Thus, from (A) and (B), we get
(n!)2 <_ nn . (n!) < (2n)!
Hence, proved.
Answered by | 08 Aug, 2012, 02:38: PM
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