CBSE Class 11-science Answered
Prove the following
Asked by | 18 Apr, 2010, 01:45: PM
Expert Answer
(tan22x - tan2x)/(1 - tan22x tan2x) =
Using a2 - b2 = (a+b)(a-b), for numerator and denominator,
[(tan2x - tanx)(tan2x + tanx)]/[(1 - tan2x tanx) (1 + tan2x tanx)] =
= tan3x tanx
Using,
tan (x+y) = (tanx + tany)/(1 - tanxtany)
(tan2x - tanx)/(1 + tan2x tanx) = tan (2x - x) = tanx
and (tan2x + tanx)/(1 - tan2x tanx) = tan (2x+x) = tan3x.
Regards,
Team,
TopperLearning.
Answered by | 19 Apr, 2010, 09:30: AM
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