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Prove that the lengths of tangents drawn from an external point to a circle are equal.

Asked by Topperlearning User 27th July 2017, 1:09 PM
Answered by Expert
Answer:

Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.

To prove: PA = PB

Construction: Join OA, OB, and OP.

It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.

OA PA and OB PB

OAP = OBP = 90o ... (1)

In OPA and OPB,

OAP = OBP (Using (1))

OA = OB (Radii of the same circle)

OP = PO (Common side)

Therefore, OPA OPB (RHS congruency criterion)

PA = PB (Corresponding parts of congruent triangles are equal)

Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.

Answered by Expert 27th July 2017, 3:09 PM
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