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prove that

Asked by priyankmalukar 8th September 2009, 10:51 PM
Answered by Expert
Answer:

Given: ABC is an isoceles triangle with AB = AC

AD = AB

To prove: BCD = 900

Proof: AB = AC   ...(1)

ABC = ACB     (angle opposite to equal sides)

we have, AD = AB

⇒ AD = AC     (from (1))

ACD = ADC    (angle opposite to equal sides)

Let ABC = ACB = ACD = ADC = x

Now in BDC

By angle sum property,

DBC + DCB + BDC = 1800

DCB = DCA+ACB = x+x = 2x

So, DBC + DCB + BDC = x + 2x + x =1800

⇒ x = 450

Therefore, BCD = 900

x+

Answered by Expert 9th September 2009, 9:27 AM
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